Question

what is the simplified form of x^2-25/x+5

Answer 1

@rayford we are given
\[\frac{x^2-25}{x+5}\]
This could be written as
\[\frac{x^2-5^2}{x+5}\]
We could use here
\[a^2-b^2=(a+b)(a-b) \]
Can you try from here?

Answer 2

@rayford do you understand till here?

Answer 3

i'm sorry i was called for something. i'm sorta understanding until here..may you continue?

Answer 4

Read my post and try to use the relation
\[a^2-b^2=(a+b)(a-b)\]
to simplify \(x^2-5^2\)
Once you do that, you'd be able to simplify easily

Answer 5

x + 5, with the restriction x -5

Answer 6

@rayford could you check again, there is a small mistake?

Answer 7

hmmm....the only conclusion i could come down to is probably
x + 5, with the restriction x 5

Answer 8

\[\frac{x^2-5^2}{x+5}\ \ =\ \ \frac{\cancel{(x+5)}(x-5)}{\cancel{x+5}}\]
\[x-5\]

Answer 9

whats the restriction though?

Answer 10

5 or -5?

Answer 11

it's on
\[x+5\]
It can't be zero. so \(x\ne -5\)

Answer 12

life saver man...thank you.

Answer 13

Do you understand this?