(y^2-y-12)/(y^2-6y+8) by (y^2+2y-15)/(y^2-7y+10) simplify
factor everything
thats the thing, i dont understand the whole concept of factoring, would you mind giving me an example please
ok well do (y^2-y-12), first thing youll do is find the factors of 12, two of these factors when added or subtracted will equal -1since you have a negative y in the middle
so the factors of 12 are , 1 and 12, 2 and 6, 3 and 4 .... i see that 4-3 will give me the negative 1 i need so ill use that
ok so you would factor each section in the equation?
well hold on the easiest way for me to explain it is with a picture your familiar with the foil method right
yes that is familiar
so were just making that your answer for the first one (y^2-y-12) is (y-4)(y+3)
ok so i think i got it, i was factoring the others ones when i finally understood what you told me, we got the first one, so would (y^2-6y+8) = (y+4)(y+2)
no since we have a negative 6 in the middle
it would just be (y-4)(y-2)
ok so you would just change the addition sign to subtraction, alright so this is what i got for the rest of them (y-4)(y+3)/(y-4)(y-2) by (Y-3)(Y+5)/(y-5)(y-2)
correct, now cancel out anything you can
actually first tell me what you mean (y-4)(y+3)/(y-4)(y-2) ???by??? (Y-3)(Y+5)/(y-5)(y-2), are you multiplying these?
i do not know, in my problem it says use complete problems to simplify the expression, so no there is no mulitplying them
btw i got (y-3)2/(y-2)^2
im just confused by what you mean by the word "by" is this division or multiplication
It is division, i just re read over the problem and it say show all work in dividing, then it gives me the equation i gave you
so youll have (y+3)/(y-2) * (y-5)(y-2)/(y-3)(y+5) you got this right
so that would be the final answer?
cancel out anything you can then that will be your answer
i got (y+3)(y-5)/(y-3)(y+5)
i dont undertand how you got that....wouldn't you cancel out the (y+5) with the (y-5)?
no you can only cancel out same factors
@panlac01 can u help out i have to leave for a few
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