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How would you solve k squared = 16? This is solving quadratic equations by taking square roots.
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\[k^2=16\] move the 16 over \[k^2-16=0\] this is a difference of squares
Am i now adding 16?
no we just moved it over difference of squares x^2-a^2=(x-a)(x+a)
woah..
so what exactly is the next step? o.o
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well k^2-16= (k-4)(k+4)=0 this means that k-4=0 & k+4=0 so we solve for both k's
oh yeah!
or you can just find the square root of both sides of the initial problem \[\sqrt{k^2}=\sqrt{16}\] just remember \[\sqrt{1}=\pm 1\]
oh yeahhh, ok cool
2 method of solving, both give the same answer
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so i leave the answer as k-4 =0 and k+4+0?
*=
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