Question

factoring question

Answer 1

\[5\cos^2x-5\sin^2x+cosx+sinx\]

Answer 2

I think you should use the quadratic formula

Answer 3

I have to factor it :P

Answer 4

oh sorry

Answer 5

Its okay:3 Anyone?

Answer 6

:(

Answer 7

*crosses fingers*

Answer 8

\[5 \cdot \cos^{2}x-5 \cdot \sin^{2}x +sinx+cosx=5\cdot(cosx+sinx)(cosx-sinx)+(sinx+cosx)\]
and now
\[5 \cdot \cos^{2}x-5 \cdot \sin^{2}x +sinx+cosx=5\cdot(sinx+cosx)(cosx-sinx +1)\]

Answer 9

o.O Okay

Answer 10

if this is confusing, put \(a=\cos(x)\) and \(b=\sin(x)\) and factor
\[5a^2-5b^2+a+b\]

Answer 11

That makes sense

Answer 12

it has nothing whatsoever to do with trig, but the all those trig functions will tend to confuse

Answer 13

\[5a^2-5b^2+a+b=5(a+b)(a-b)+a+b=(5(a-b)+1)(a+b)\]

Answer 14

:D figured it out! I can do "5a2−5b2+a+b" :P

Answer 15

Thanks
:)