Find a pair of factors for each number by using the difference between two squares. a. 45 b. 77 c. 112
a) Notice how 45 = 9*5 45 = (7+2)*(7-2) 45 = 7^2 - 2^2 45 = 49 - 4 ------------- So going backwards, you can say 45 = 49 - 4 45 = 7^2 - 2^2 45 = (7+2)*(7-2) 45 = 9*5
ok so what do i do next
Use this technique to do parts b) and c) Let me know what you get
hold on i will be right back
alright
does it make a difference if you go backwards or not also
I'm just showing you how I got the stuff under the "------" line. You don't have to go backwards if you know how to go forwards (if that makes any sense)
oh ok yes it does ok hold on
sure thing
could you help
where are you stuck?
still on 77... :(
that's ok
77 = 11*7 77 = (9+2)*(9-2) 77 = 9^2 - 2^2 77 = 81 - 4 ------------------ Now go backwards 77 = 81 - 4 77 = 9^2 - 2^2 77 = (9+2)*(9-2) 77 = 11*7 So the idea is that you work out the first part on scratch paper. Then the second part is what you do on your hw
ok i am stuck on the (+) (-) part on 112
on the first part so far i have 112= 8*14
so 112 = 8*14 112 = (11-3)*(11+3)
ok so i got 112=8*14 112=(11+3)(11-3) 112=11^3- 3^3 112=116-4
you square, not cube
so your 3rd step should be 112 = 11^2 - 3^2
oh ok soo what do i do next
11^2 = 121, 3^2 = 9 so 112 = 11^2 - 3^2 becomes 112 = 121 - 9
Now go backwards: start with 112 = 121 - 9 and work your way up to find the factorization for 112
112=121-9 112=11^2-3^2 112=(11-3)*(11+3) 112=8*14
good, you nailed it
ok so what do i put as the answer? the whole things we just worked on
what you just wrote is your answer for part c)
the other parts are similar (just use different numbers)
so a. is all that with 45 and b is all that with 77 and c. is all that with 112 is the answers?
yes pretty much, half is scratch work so you know how to start each one
but you might as well include it
alrighty Thanks so much
yw
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