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Mathematics 20 Online
OpenStudy (anonymous):

Use intercepts to graph the line given by 2x-3y=6.

OpenStudy (anonymous):

k so I already got x=3 and y=-2 then what do I do?

OpenStudy (anonymous):

Hello?

OpenStudy (anonymous):

join the points (3;0) and (0;-2) and you'll have your line

OpenStudy (compassionate):

Just like Ghass said.

OpenStudy (anonymous):

|dw:1345668133141:dw| thats all?

OpenStudy (anonymous):

where are the points?

OpenStudy (compassionate):

You graphed it wrong.

OpenStudy (anonymous):

er (3,0) and (0,-2) ? or what is it?

OpenStudy (compassionate):

|dw:1345668207062:dw| Should look something like this.

OpenStudy (anonymous):

but how did you graph it just from knowing that x=3 and y=-2?

OpenStudy (anonymous):

gtg but keep typing LOL

OpenStudy (compassionate):

(3, y) (x, -2) Look at your graph points. Look at your graph. Now graph 3 on your x-axis because x=3 Now graph -2 on your y axis because y=-2 Your graph always takes the form (x, y) Meaning if something is like this (10, y) You're graphing 10 on the x-axis If something is like this (x, 10) You're graphing 10 on the y-axis. Usually you'll see something like (0,2) (2,0) (2,2) etc. For the first on(0,2) The same rule applies. Ignore the zero and just graph 2 on the y-axis

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