Question

Write the equation of a circle whose center is at the origin and that contains the point (-3, 0).

Answer 1

Hint:

The general equation of any circle is (x-h)^2+(y-k)^2=r^2

Answer 2

where (h,k) is the center and r is the radius

Answer 3

Keep in mind that the origin is the point (0,0). So to find the radius, you need to find the distance from (0,0) to (-3,0)

Answer 4

3

Answer 5

yes

Answer 6

so r = 3

Answer 7

the center is at the origin, so (h,k) =(0,0) which means h = 0 and k = 0

Answer 8

and x>?

Answer 9

I'm not sure what you mean, but the equation

(x-h)^2+(y-k)^2=r^2

becomes

(x-0)^2+(y-0)^2=3^2

x^2 + y^2 = 9