Write the equation of the line in slope-intercept form. perpendicular to y= 2x+6 and passing through (-4,2)
do I still use the point slope form.. formula?
y-y1=m(x-x1)
yes that is correct and then you substitute the given values.
Do I keep the slope as 2?
no, slope perpendicular to 2 is -1/2
y = -1/2x
okay the reciprocal
yup
perpendicular means, the slope for the other line is negative reciprocal
I got a weird answer... y = \[\frac{ -1 }{ 2}x\] + 0
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I checked the answer key and it says it is wrong....
plug the values in correctly into the point-slope form
yup it must be y=-1/2x+4
Yeah that is the answer
What did you do that I did not do?
y-2=-1/2(x+4)
\[y-2=m[x-(-4)]\] the perpendicular slope of 2 is -1/2
yeah I got that...
i think that the answer in your notes is wrong and it should be y=-1/2x as y=-1/2(x+4)+2 simplifies to y=-1/2x-2+2 thus y=-1/2x
\[y-2=-\frac{ 1 }{ 2 }[x-(-4)]\]
Oh so I was right... y=-1/2x + 0
when you add 2 on both sides, what happens to the right side?
it looks like it. The notes went wrong on the substitution. to get the answer that you have in the notes you need to have y=-1/2(x-4)+2
you are correct: \[y-2+2=-\frac{ 1 }{ 2 }x-2+2\]
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