Question

for the first half of a journey a car has a constant velocity of V1 and after that it has a constant velocity of V2. what is the average velocity?

Answer 1

i was thinking V1+V2/2 but thats wrong :/

Answer 2

i know that velocity= change in distance/change in time..

Answer 3

This is my forte' ^^

Answer 4

^^

Answer 5

so what do we do?

Answer 6

let it travel with v1 for t1 covering s/2.
& with v2 for t2 covering s/2. Okay?

Answer 7

okay

Answer 8

So, v(avg) =s/t1+t2.

Answer 9

Oops. silly mistake.. forgot the equations :0

Answer 10

But did u see how i did it?

Answer 11

write equations for t1 & t2 & add them up.

Answer 12

okay brb

Answer 13

@rajathsbhat where did your drawing go?

Answer 14

I deleted it. It was wrong.

Answer 15

v1=(s/2)/t1 then t1= (s/2)/v1 and v2=(s/2)/t2 then t2=(s/2)/v2
then average v: s/(s+(v1+v2) ? idk what am doing