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Mathematics 16 Online
OpenStudy (anonymous):

x+8/7 - x+3/7

OpenStudy (anonymous):

Get the variable by itself 7x - 3 = 18 7x = 18 + 3 7x = 21 x = 3

OpenStudy (anonymous):

how did you get 7x-3=18?

OpenStudy (anonymous):

subtract and write in simplest form.

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

I am confused :/

OpenStudy (anonymous):

don't be confused just do what i did there am sure of it

OpenStudy (anonymous):

But i dont understand how you got that.

OpenStudy (phi):

can you use the equation editor, or put in parens? is it \[\frac{x+8}{7} - \frac{x+3}{7} \]

OpenStudy (anonymous):

yeah thats the equation

OpenStudy (phi):

you are subtracting 2 fractions that have the same denominator. subtract the tops, and keep the same denominator the top is (x+8) - (x+3) the bottom is 7 can you do (x+8) - (x+3)

OpenStudy (phi):

remember -(x+3) is the same as -1*(x+3) distribute the -1 by multiplying each term inside the parens by -1

OpenStudy (anonymous):

so (x+8)(x-3)?

OpenStudy (phi):

so (x+8)(x-3)? that means multiply you want (x+8) - (x+3) the first step is get rid of the parens. the ones around (x+8) we can ignore: x+8 -(x+3) to get rid of parens in -(x+3) remember -(x+3) is the same as -1*(x+3) distribute the -1 by multiplying each term inside the parens by -1

OpenStudy (anonymous):

so would it equal 5 on top?

OpenStudy (phi):

how did you get it?

OpenStudy (anonymous):

by subtracting x+8 and x-3

OpenStudy (phi):

you mean subtracting x+8 - (x+3) right? x+8-(x+3)= x+8-x-3= x-x + 8-3= 0+5= 5 yes so the answer is \[ \frac{5}{7} \]

OpenStudy (anonymous):

okay i understand thank you :)

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