x+8/7 - x+3/7
Get the variable by itself 7x - 3 = 18 7x = 18 + 3 7x = 21 x = 3
how did you get 7x-3=18?
subtract and write in simplest form.
yeah
I am confused :/
don't be confused just do what i did there am sure of it
But i dont understand how you got that.
can you use the equation editor, or put in parens? is it \[\frac{x+8}{7} - \frac{x+3}{7} \]
yeah thats the equation
you are subtracting 2 fractions that have the same denominator. subtract the tops, and keep the same denominator the top is (x+8) - (x+3) the bottom is 7 can you do (x+8) - (x+3)
remember -(x+3) is the same as -1*(x+3) distribute the -1 by multiplying each term inside the parens by -1
so (x+8)(x-3)?
so (x+8)(x-3)? that means multiply you want (x+8) - (x+3) the first step is get rid of the parens. the ones around (x+8) we can ignore: x+8 -(x+3) to get rid of parens in -(x+3) remember -(x+3) is the same as -1*(x+3) distribute the -1 by multiplying each term inside the parens by -1
so would it equal 5 on top?
how did you get it?
by subtracting x+8 and x-3
you mean subtracting x+8 - (x+3) right? x+8-(x+3)= x+8-x-3= x-x + 8-3= 0+5= 5 yes so the answer is \[ \frac{5}{7} \]
okay i understand thank you :)
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