A jet plane has a takeoff speed of vto = 75 m/s and can move along the runway at an average acceleration of 1.3 m/s2. If the length of the runway is 2.5 km, will the plane be able to use this runway safely?
ok so 2 equations \[v=v_o+at\] and \[x=\frac{1}{2}at^2+v_ot+x_o\] the first equation calculates velocity at time t the 2nd equation calculates distance travelled at time t
ok assuming that initial velocity and initial position are both equal to 0 the take off velocity is 75 and acceleration is 1.3 so determine the time it takes to reach 75 m/s or 75=1.3t solve t
Yes
it will
t = 57.69
once you find t you substitute the values into the position equation and determine how far it will travel so \[x=\frac{1}{2}(1.3)t^2\]
37.49
calculate that again i got 2163 m
Wait thats not it
You're right. Forgot the squared
ok now is 2163m less than 2.5km???
the plane needs to travel 2163 meters in order to reach takeoff velocity and the runway is only 2.5km
337 meters
337meters means absolutely nothing unless it asked for how much of the runway wasnt used all you just need to realize is 2.5km is the same as 2500 m and that because the plane only needed 2300m to take off, then there was enough room
You're absolutely right
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