Question

A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.

Answer 1

You must be able to start this one off for yourself. Can you show us what you have so far?

Answer 2

1000(1.15)=100?

Answer 3

hi

Answer 4

hi

Answer 5

can u help me :)

Answer 6

ok ask you self . what is the value of motor scooter after 1 year?

Answer 7

150$....

Answer 8

?

Answer 9

no

Answer 10

so what the question is really saying is , the value of motor scooter goes down by 15%.

Answer 11

100 = 1000e^(-0.15t)

Answer 12

850$

Answer 13

@SNSDYoona
we dont give answers out like that.

Answer 14

1000 = the starting money that u purchased it
the basic formula for this exponential decay and growth functions is
A= Ye^(kt)

Answer 15

thts why i give him the answer first to see if he does any calculation wrong then explain to him if he doesnt get it

Answer 16

thats why we don't give answers out. you need to explain the exponential formula. Not just stated it!!!

Answer 17

A = the amount u left after a certain period of time
Y = initial amount started with
k = ur rate of decay/growth
t= the time

Answer 18

0.1=(-0.15t)

Answer 19

?

Answer 20

have u learn natural logs?

Answer 21

from 100 = 1000e^(-0.15t)
u simplify it then u get down to
0.1= e^(-0.15t)
then u take the natural logs off both side
u get ln(0.1) = -0.15t
then u solve for t
ln(0.1)/0.15 = t

Answer 22

i got 0.666

Answer 23

u shud get 15.35

Answer 24

use ur calculator.. did u type in correctly?

Answer 25

i divide .1 by .15?

Answer 26

nonono u use ln << ln = natural log

Answer 27

look at ur calculator and search for ln

Answer 28

press ln and then (0.1)

Answer 29

then divide by (-0.15)

Answer 30

im using google calculator i dont have 1

Answer 31

15.3?

Answer 32

yeap

Answer 33

v(t) = 0.85(1000)t; the value will fall below $100 in about 18 yr.
v(t) = 1000(0.85)t; the value will fall below $100 in about 18 yr.
v(t) = 0.85(1000)t; the value will fall below $100 in about 14.2 yr.
v(t) = 1000(0.85)t; the value will fall below $100 in about 14.2 yr.

Answer 34

u still there

Answer 35

hi

Answer 36

hi