Question

A juggler is performing an act by juggling several balls. The juggler throws the balls up at an initial height of 3.9 feet with a speed of 14.8 feet per second. If the juggler did not catch a ball, about how long will it take the ball to hit the floor?

1.45 secs

1.14 secs

0.28 secs

0.21 secs

Answer 1

Do..u knw kinematics equations of motion

Answer 2

um.....no

Answer 3

^^that sounds like physics

Answer 4

V = u + at

Answer 5

um... i thought it was H(t)= -16t^2+vt+s

Answer 6

first we need to convert feet to meter

Answer 7

ok...whats next

Answer 8

then the time it takes to reach the maximum height

Answer 9

wait why do i change it from feet to meters?

Answer 10

because we are going to use a=g=-9.81m/s^2

Answer 11

oh okay

Answer 12

Now, can u?

Answer 13

whats the a and g?
sorry

Answer 14

that is accleration

Answer 15

ok.......walk me through

Answer 16

convert 3.9 feet into meter

Answer 17

about one meter?

Answer 18

14.8 feet per second in meter per second?

Answer 19

oh okay 4 meters and something

Answer 20

3.9 feet = 1.18872m and 14.8 feet per second=4.51104 meter per second

Answer 21

now,v=u+at
0=4.51 + (-9.81)t
t=0.46seconds

Answer 22

Again, v^2=u^2+2as
0^2=(4.51)^2 + 2(-9.81)s
s=1.04 m

Answer 23

So, maximum height = 1.19+1.04 m = 2.23m

Answer 24

Now, s=ut+1/2 at^2
2.23 = 0*t + 1/2 (9.81) t^2
t=0.67 seconds

Answer 25

So, total time = 0.46+0.67 =1.13 seconds

Answer 26

got it?

Answer 27

ohh okay.

Answer 28

thanks

Answer 29

welcome