Question

8| x + 3/4 | < 2

Answer 1

So we want to solve for x.
Can you isolate this part, |blah| ?

Answer 2

You have 8 times |blah|<2
To undo multiplication by 8 you _____?______
What goes in that blank?

Answer 3

Foil then first so you get \[8x+6<2\]
and then u could subtract 6 both side and get \[8x <-4\]
finally u divide 8 both side get\[X <-1/2\]

Answer 4

@EP Please don't just give the answer. Also that is not the full answer.

Answer 5

That is what I was trying to get @androidonyourface to say to begin with :(

Answer 6

So after dividing 8 on both sides can you tell us what we will have @androidonyourface ?

Answer 7

Sorry :|
@androidonyourface just be careful of the absolute value sign, okay? and do what the cool person says :p

Answer 8

Right!
1)If you have |f(x)|<a where a is some positive number
then you will have -a<f(x)<a .
2)If you have |f(x)|>a where a is some positive number
then you will have f(x)<-a or f(x)>a

Which one do we have here?
1 or 2?

Answer 9

sorry i was letting the dog out ,

Answer 10

let me do it again

Answer 11

ok

Answer 12

@EP If you are going to help, then guide and don't just give the answer please.

Answer 13

even if you solved it thats not the full answer i just need to know how to solve it so I can graph it which is the problems question

Answer 14

What do you get after dividing 8 on both sides?
And look at your question and what I said and tell me is your problem like 1 or 2?

Answer 15

1

Answer 16

Perfect! :)
Ok so after dividing 8 on both sides and seeing your problem is like 1 then what do you get?
I will check for accuracy.
You can draw it if you want.

Answer 17

-4 and the other 8 cancels out?

Answer 18

no i mean x < -1 or x > - 1/2

Answer 19

Well you told me your problem was like this "1)If you have |f(x)|<a where a is some positive number
then you will have -a<f(x)<a ."

Answer 20

like if i were to graph the solution on a number line it would be x -1 or x > -1/2

Answer 21

Before we can graph your inequality needs to be right and right now it isn't.

Answer 22

We have after dividing 8 on both sides:
\[|x+\frac{3}{4}|<\frac{2}{8}\]
This has this form |f(x)|<a
So that means I just use 1
I plug into here:
-a<f(x)<a

f(x)=x+3/4
And
a=2/8 or 1/4 you can say

Answer 23

-1 < x < - 1/2

Answer 24

Right on! :)

Answer 25

:)

Answer 26

Ok so if we were to draw a number line: