for which x-value does f(x)=3x^4-2x^3-5x^2-7x+10 go up?
@satellite73
U mean increases
yes
i know we have to find the second derative..
i got this for first: y' = 12x^3-6x^2-10x-7 y''= 63x^2-12x-10 but then idk what to do next
y'>0
i don't see an easy way to do this
Find the intervals for which y'>0
first factor 12x^3-6x^2-10x-7
well we actually want to know when the convex goes up?
you want \(12x^3-6x^2-10x-7>0\) but it doesn't factor or anything, so who knows?
careful here is the question "over what interval is \(f\) increasing?" or is it "over what interval is \(f\) concave up?" they are two different things
how do you know that y'>0 ?!
i cant find factors
i don't know other than to use technology
is the concave up increasing
going up
so we need the second derivative
@bronzegoddess concave up and increasing are two very different things
okay let me rephrase for which value of x is the convex going up?
going up is not concave up here is an example of going up, concave down |dw:1345900327953:dw|
@bronzegoddess if it concave up or down thats didnt mean its increasing
i cannot figure out what " the convex going up" means can you write the question exactly as it is written?
it is in dutch and thats what it is asking..
for which x-value is the convex side going up? sorry i forgot side @satellite73
still doesn't make sense?
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