Question

In the Absolute value inequality: |3x-2| + 7 > 11
In the final outcome, would one of the 2 answers be a fraction? or did I make a mistake? I got x>2 and x<3\2

Answer 1

You basically, you subtracted 7 from both sides and got

|3x-2| > 4

Then the next thing you did was:
\(-4 >3x - 2 > 4\)

Then you continued solving from there, right?

Answer 2

The way I did it was by creating 2 separate equations, Like this:
3x-2>4
3x-2<-4

Then I solved both of them, Is that incorrect?

Answer 3

you're right but one of your answers is wrong

Answer 4

The one that says 3x-2<-4?

Answer 5

oh it must be -3/4?

Answer 6

@reich6709, it would be easier on you if you used the general formula:

\(|x - a| < b\) can be re-written as \( -b < x - a < b\)

Answer 7

\(|x - a| < b \equiv -b < x - a < b\)

Answer 8

I see, I'll try that now

Answer 9

Same answers

Answer 10

3x-2<-4=>3x<2-4=>3x<-2=>x<-2/3