Question

A machinist creates a washer by drilling a hole through the center of a circular piece of metal. If the piece of metal has a radius of x + 10 and the hole has a radius of x + 6, what is the area of the washer?

Answer 1

@hal_stirrup im here now ;)

Answer 2

hi

Answer 3

my last one

Answer 4

ok what is the area of hole?? right.

Answer 5

6

Answer 6

A(washer) - A(hole) = π (x+10)^2 - π (x+6)^2 = π (8x+64)

Answer 7

@dan18

would you rathe help daboss33 understand how yo think about the problem instead of solving it.!!

Answer 8

@hal_stirrup
are you mad? sorry I thought it would be much more easier to understand since the solution is given already, the solution I've given speak itself.

A(washer) - A(hole)
= πR^2 - πr^2
= π(x+10)^2 - π(x+6)^2
=π(x^2+20x+100) - π(x^2+12x+36)
= π(8x+64) sq. unit