A machinist creates a washer by drilling a hole through the center of a circular piece of metal. If the piece of metal has a radius of x + 10 and the hole has a radius of x + 6, what is the area of the washer?

Question

anonymous · Answer

@hal_stirrup   im here now ;)

anonymous · Answer

hi

anonymous · Answer

my last one

anonymous · Answer

ok what is the area of hole?? right.

anonymous · Answer

6

anonymous · Answer

A(washer) - A(hole) = π (x+10)^2 - π (x+6)^2 = π (8x+64)

anonymous · Answer

@dan18    

would you rathe help daboss33 understand how yo think about the problem instead of solving it.!!

anonymous · Answer

@hal_stirrup
are you mad? sorry I thought it would be much more easier to understand since the solution is given already, the solution I've given speak itself.

A(washer) - A(hole)
   = πR^2 - πr^2 
   = π(x+10)^2 - π(x+6)^2
   =π(x^2+20x+100) - π(x^2+12x+36)
   = π(8x+64) sq. unit