Question

Is there any way to calculate the volume of a graph if you're only given cross sectional area?

Answer 1

@cindybear13 volume of a graph?
it should be a solid, created by revolving the curve about some line.
ummm are you studying calculus?

Answer 2

I have been given coordinates that show what appears to be a cross sectional graph, so it is 2D. I am studying calculus, only grade 12 calc though.

Answer 3

could you share the graph here? and the full question

Answer 4

1. From a reference point 'O', the ore body goes out 500 east at a depth of 1800 meters and at a point 200 meters west, at a depth of 3200 meters.
2. Between these two points the upper boundary of the ore body is represented as a linear function.
3. The lowest point in the ore body occurs at 100 meters east of the reference point 'O' at a depth of 5000 meters.
4. The lower boundary of the ore body is parabolic in shape.
5. The parabola would exit the ground at a point 600 meters east and 400 meters west of the reference point.
6. The ore body runs for 850 meters in a north-south direction.
7. The cross sectional area of the ore body is unchanged along its length.

Answer 5

From this information a graph of this was created

Answer 6

@cindybear13 I'm sorry but this is too difficult for me, I think @myininaya @suyash011 @amistre64 @satellite73 @TuringTest might be able to help

Answer 7

The main two points that I know are of use but I dont understand how to use them are the last two. I really hope that someone can help I'm going mad trying to find answers :(

Answer 8

@cindybear13 was the graph given in the question or you drew it?

Answer 9

I determined it but I have tested it and it works.

Answer 10

I formed the equations based on the information given. I just dont know how point 6 and 7 are supposed to be utilised

Answer 11

are you rotating about an axis?

Answer 12

I think the graph has to be redrawn

Answer 13

Not that I know of because the teacher hasn't taught us 3D graphing yet so I'm not sure what is expected to be done.
Well the functions for these two lines are y=0.02x^2-4x-4800 and y=2x-2800 if you want to try them yourself?

Answer 14

it runs in a north south direction for 850 meters, so this forms a cylindar