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Mathematics 18 Online
OpenStudy (anonymous):

\(f(x) = e^{sinx}cosx\). \(f'(x)\)is equal to?

OpenStudy (anonymous):

well..id say use product rule

OpenStudy (anonymous):

cos^2x.e^sinx e^sinx(sinx)

OpenStudy (anonymous):

\[\large (e^{\sin x}\cos x)'=(e^{\sin x})'\cos x+e^{\sin x}(\cos x)'\]

OpenStudy (anonymous):

got it from here?

OpenStudy (anonymous):

chain rule from here?

OpenStudy (anonymous):

yeah chain rule for \[(e^{\sin x})'\]part :)

OpenStudy (anonymous):

I got \((cos^2x - sinx)e^{sinx}\) thanks for your help :D

OpenStudy (anonymous):

welcome :)

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