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\(f(x) = e^{sinx}cosx\). \(f'(x)\)is equal to?
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well..id say use product rule
cos^2x.e^sinx e^sinx(sinx)
\[\large (e^{\sin x}\cos x)'=(e^{\sin x})'\cos x+e^{\sin x}(\cos x)'\]
got it from here?
chain rule from here?
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yeah chain rule for \[(e^{\sin x})'\]part :)
I got \((cos^2x - sinx)e^{sinx}\) thanks for your help :D
welcome :)
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