Question

g(t)=√3:(t-63)

answer should be in interval notation

Answer 1

is it\[\sqrt{\frac{3}{t-63}}\]?

Answer 2

yeah.

Answer 3

the 3 is small above the square root symbol

Answer 4

3rt(t-63) ; or cbrt(t-63) are pretty good keyboard notation for indexes

Answer 5

so its\[\sqrt[3]{t-63}\]

Answer 6

what defines an answer in order to put it into interval notation ???

Answer 7

it can't be zero underneath the sqrt right?

Answer 8

odd functions are allowed to go negative

Answer 9

cbrt(-8) = -2 since, -2*-2*-2 = (-2)^3 = -8

Answer 10

and this is an odd function?

Answer 11

is 3 and odd number?

Answer 12

haha yeah.

Answer 13

then yes :)

Answer 14

you looking for domain, or range?

Answer 15

domain :)

Answer 16

and we aint got any fractions do we ?

Answer 17

its just t-63 under there; and not 1/(t-63) right?

Answer 18

yeah just t-63

Answer 19

then there are no restrictions to be had; all real numbers can be used

domain is then \((-\infty,\infty)\)

Answer 20

how do you know for sure whether there are restrictions or not? I have a hard time determining this...

Answer 21

there are a few things to keep in mind; you cant divide by zero, you cant have logs that are less than or equal to zero .... even radicals cant be negative.

Answer 22

thats pretty much it ....

Answer 23

okay gotcha. so, would f(x)=sqrt(73.5-7x)... I solved and somehow got 10.5..?

Answer 24

is sqrt and even or odd radical?

Answer 25

even..?

Answer 26

correct , 2 is even :)

so, we cant have negative values; so determine the solution to:\[73.5-7x >= 0\]

Answer 27

And I got

Answer 28

nice

Answer 29

so, lets use 10.5, since we can be equal to it we use the = notation connected by a bar