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Mathematics 16 Online
OpenStudy (anonymous):

Help ?

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

Remember that the square root cuts the exponent in half

jimthompson5910 (jim_thompson5910):

So \[\Large \sqrt{p^6} = p^3\]

jimthompson5910 (jim_thompson5910):

and \[\Large \sqrt{p^2} = p^1 = p\]

jimthompson5910 (jim_thompson5910):

Also \[\Large \sqrt{9p^6} = \sqrt{9}\sqrt{p^6}\] \[\Large \sqrt{9p^6} = 3p^3\]

jimthompson5910 (jim_thompson5910):

So overall... \[\Large \sqrt{p^6}+\sqrt{9p^6} + 3\sqrt{p^6} - \sqrt{p^2}\] \[\Large p^3 + 3p^3 + 3p^3 - p\] \[\Large 7p^3 - p\] ------------------------ This means \[\Large \sqrt{p^6}+\sqrt{9p^6} + 3\sqrt{p^6} - \sqrt{p^2}\] simplifies to \[\Large 7p^3 - p\]

jimthompson5910 (jim_thompson5910):

it's a lot, but hopefully it makes sense

OpenStudy (anonymous):

Yeah I know

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