Question

Find the discontinuaties and zeros of (2x^2+5x-12)/(x+4)

Answer 1

I got the discontinuity at (-4,-11) is that right? And I still need help with the zero(s).

Answer 2

Okay, I got the zero of 3/2, is that correct?

Answer 3

\[
\frac{2 x^2+5 x-12}{x+4}=\frac{(x+4) (2 x-3)}{x+4}=2 x-3
\]

Answer 4

x =2/3 is correct

Answer 5

x=-4 is the only removable discontinuity.

Answer 6

How did you get the -11?

Answer 7

That's where the point is on the graph, I wasn't stating another discontinuity.

Answer 8

Ok. But -4 is a removable discontinuity.

Answer 9

Alright, thank you.

Answer 10

yw