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Chemistry 21 Online
OpenStudy (anonymous):

The reaction is first order with respect to cyclopropane with k = 9.2 s-1 at 1000°C. a) Calculate the half-life of the reaction.

OpenStudy (anonymous):

I have to put the equation of half life I guess.

OpenStudy (anonymous):

How much of a 3.00 g sample of cyclopropane remains after 0.50 sec at 1000°C

OpenStudy (anonymous):

thats the tricky part

OpenStudy (xishem):

First calculate the half-life and post that number.

OpenStudy (anonymous):

0.074

OpenStudy (xishem):

That's right. Now do you happen to know the half-life equation that involves initial amount, final amount, and elapsed time?

OpenStudy (anonymous):

I do know the equation

OpenStudy (anonymous):

ln[a]=k t1/s+ln(value of given molecule)

OpenStudy (xishem):

That's right. Be sure that you have a NEGATIVE sign in front of the kt:\[\ln[A]=-kt+\ln[A]_0\]It's as simple as plugging in the values you know and solving for [A]

OpenStudy (anonymous):

but my answer is wrong.

OpenStudy (xishem):

I'm getting 0.0302g

OpenStudy (anonymous):

first u multiply the value of k with time?

OpenStudy (anonymous):

how to calculate it with ln?

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