Question

efsadfa

Answer 1

@helder_edwin
How do you something like this?

Answer 2

split the vectors. for example
\[ \large (3t-1,2t,4t+1)=(3t,2t,4t)+(-1,0,1)
=t(3,2,4)+(-1,0,1) \]

Answer 3

and the other one would equal t(2,-1,-1) + (3,0,-1) then what?

Answer 4

what about the first one??

Answer 5

the first one would be t(3,1,-2) + (1,1,0)

Answer 6

but what does that show

Answer 7

the vector that has the t ses the direction of the line.
for two lines to be parallel the have to be equal

Answer 8

so that would mean these are intersecting?

Answer 9

to answer that solve this
\[ \large (3t+1,t+1,-2t)=(2t+3,-t,-t-1) \]

Answer 10

How would you solve that

Answer 11

when are two vector equal???

Answer 12

I am unsure of that

Answer 13

\[ \large (a,b,c)=(d,e,f)\Leftrightarrow a=d\wedge b=e\wedge c=f \]

Answer 14

what is the symbol between d and b

Answer 15

the logical AND

Answer 16

I have never see that how do i apply that

Answer 17

\[ \large 3t+1=2t+3 \]
go on

Answer 18

t =2

Answer 19

then what?

Answer 20

u have two more equations

Answer 21

t+1=-t
-2t=-t-1

Answer 22

t = .5 and t = 1 now what?

Answer 23

I dont know where to go from here..

Answer 24

u got three different solutions. this means the lines do not intercept

Answer 25

So they are skew lines?

Answer 26

yes. we have ruled the other options out