Question

how can i factor 10t2−33t+26 completely

Answer 1

check the question again @michaelshaw

Answer 2

it says "factor completely" 10t2−33t+26

Answer 3

@mathslover

Answer 4

oh k I got it now

Answer 5

\[\large{10t^2 -20t -13t +26}\]
\[\large{10t(t-2)-13t(t-2)}\]

Answer 6

can u tell me what will we get after taking (t-2) common?

Answer 7

(10t-13)(t-2) ?

Answer 8

great work so that is ur answer

Answer 9

thanks man!

Answer 10

@mathslover

Answer 11

i have another one if ur up for it..

Answer 12

No problem also:
\[\huge{\mathbb{WELCOME}\space \textbf{TO}\space \cal{OpenStudy}}\]

Answer 13

33t2+13t−6 AND THANKS I LIKE IT HERE!

Answer 14

33t^2+13t-6

Answer 15

@mathslover

Answer 16

please post this as a new question it will be answered there

Answer 17

ok

Answer 18

i dont know how to, did i just do it?

Answer 19

yes

Answer 20

thanks