Question

Assume that nay two elctron are indistinguishable.An atomic Orbital.is to be specified by four quantum numbers n , l , msl , ms calculate the No of ways two electron can be accomodated in 3d orbitalsof an atom?

Answer 1

I can find total number of ways by listing them all but that would be rather lengthy.. and i don't know if there is a special formula to calculate the number of ways. But i know that all four quantum numbers can't be same at the same time!

Answer 2

ie Pauli's Exclusion Principle

Answer 3

u knw the answer it should be 45 ways

Answer 4

LOL, I would have done it by listing all 45 ways but that is too lengthy.. And there is chance that you might miss a few. I guess there should be a formula for this one! Google it!

Answer 5

Can..u Do...it..)) i dont find..any

Answer 6

Your question doesn't quite make sense. Assume that no two electrons are indistinguishable? So, assume that any two electrons are distinguishable? That doesn't make sense. And in 3d orbitals doesn't make sense either, because 3d is not a number. Do you mean how many ways could they be arranged within the 3d orbital?

Answer 7

yes...hw many two electron can acoomodated in 3d

Answer 8

d orbital can accomodate 10 e

Answer 9

as far as i understand the question..i guess it says spin of electrons are same ..(no two electrons are identifiable) so..i think number of ways could be two...either with opposite spin or with same spin...by the way i really didn't get your question? last option is you can apply permutation..but that will give you the same answer :)

Answer 10

*indistinguishable

Answer 11

How many ways can two distinguishable electrons be accommodated in the 3d orbital? Is that the question?

Answer 12

yes

Answer 13

25.

Answer 14

What @jemurray3 finally understands is the actual question!

Answer 15

the answer should be 45

Answer 16

i am getting 120

Answer 17

:(

Answer 18

If they are distinguishable, they have opposite spin, i.e. one is spin up and the other is spin down. If that is the case, there are 25 possible ways that they can be arranged (with differing values of their orbital angular momentum) in the 3d orbital. If they are indistinguishable, i.e. they have the same spin, then there are a further 20 possible ways they can be accommodated, for a total of 45. However, that is not taking into account that if there are 20 ways to accommodate 2 identical electrons, there are in reality only 10 distinct arrangements, which brings the total down to 35.

Answer 19

@ghazi n and l are already nailed down. We have the freedom to play with the z-component of the orbital angular momentum and the spin. There are 5 possible values for the ml (-2, -1, 0 , 1, 2) and two possible values for ms (+1/2, -1/2). If they are distinguishable, with opposite spins, then we have no freedom with ms. There are five values of ml that the spin up electron can take, and five values that the spin down electron can take, so 5*5= 25.

Answer 20

exactly

Answer 21

if they are indistinguishable, then they can't have the same value of ml, so instead of 5*5 we get 5*4 = 20. But if they're REALLY indistinguishable, we have to cut that in half to 10.

Answer 22

hmm..that seems a proper logic @Yahoo! what say?

Answer 23

it seems to be

Answer 24

but my book says it is 45

Answer 25

If you don't cut that 20 to 10 then you have your answer. If that's the case, I suspect what's really being asked is that you count all the possible ways the electrons can be distributed without worrying about the fact that they're indistinguishable so some of those arrangements are redundant.

Answer 26

so..@Jemurray3 wat do u think

Answer 27

What do you mean? I have given my best answer to the question.