give a formula for the solution y(x) of the differential equation y'(x) = 0.4y(x) with y(0)=8
hmm...a separable differential equation\[ y'(x) = 0.4y(x)\]\[\frac{\text{d}y}{\text{d}x}=0.4y\]\[\frac{\text{d}y}{y}=0.4\ \text{d}x\]
but what is the y(x) function?
i got y(x) =e^(0.4(0.5x^2+20)) but its incorrect
first,did u integrate that? dy/y=0.4x what did u get? write that
i got y'(x)/0.4y(x) = 1
this is all steps i wrote it, but it still incorrect
this is simpler than u solved,u just need to integrate this on both sides, \[\frac{dy}{y}=0.4dx\]
someone suggest me write as this ln(y) = 0.4x +c then y(0)=8 will gives me ln(8)0=c. therefore, ln(y)=0.4x+ln(8))
is that the same thing as yours?
after integrating that u WILL get that: as \[\int\limits_{}^{}dy/y=\ln y\] and \[\int\limits_{}^{}0.4dx=0.4x+c\] so yes,same thing
i got the lny(x) = 2x/5 + 8
but how did u get c as 8?
c is ln(8)
y= e^(2x/5 + ln(8))
now thats correct :)
thank you!
welcome :)
also can you help me on this one?
sure.
i did several times, still incorrect. i got the tips that need use integral by part, u = sinIntegral(x)
this seems difficult for me too,need some time.
i think we don't need take the sinIntegral(x) apart. we could see it as a whole thing?
i have never solved such integral.....this reference gives the integral of sinintegral x: http://mathworld.wolfram.com/SineIntegral.html
emm ok. thx for taking ur time
i would hand this back to @mukushla
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