Question

how do i make x the subject of this formula..equation posted in replies..

Answer 1

\[3x ^{2} +y -4 =0\]

Answer 2

isolate x^2 first

Answer 3

1) add \(4\)
2) subtract \(y\)
3) divide by \(3\)
4) take the square root (don't forget the \(\pm\) )

Answer 4

what do i do once i've got here..\[x ^{2}=\frac{ -y+4 }{ 3 }\]..do i square root both sides

Answer 5

yes, yes,do it.

Answer 6

yes, just stick a big fat radical over the whole thing
but don't forget the \(\pm\)

Answer 7

so thiis would be my answer? \[\sqrt{ x= \frac{ -y+4 }{ 3 }} \]

Answer 8

or this?\[\sqrt{\frac{ -y+4 }{ 3 }} = x\]

Answer 9

the 2nd one,but u forgot +- sign,even when told twice not to...

Answer 10

i dont know what that means..i've had real bad teachers

Answer 11

okk,just write it like this
\[x=\pm \sqrt{\frac{ -y+4 }{ 3 }} \]

Answer 12

oh ok..so i should do that on all square roots like this?

Answer 13

yes.
because if
\[x^2=a\]
\[x=\pm a\]

Answer 14

ok thanks for your help

Answer 15

welcome :)