Find the distance traveled in 15 seconds by an object moving with a velocity of v(t)=20+7cos(t) feet per second.
@ccjeff \[Distance= Velocity \times time \]
Could you try now?
so it'd be 15*v(t)? I'm more asking for solving v(t)
put the value of v(t) given in the question v(t)=20+7cos(t)
would cos be in radians or degrees? because i get to 300+105cos(15) and thats all I need to solve for.
oops, I'm sorry. Do you know integration?
It's been awhile.
integrate the equation wrt to time....make t=0 to find the constant....and then substitute t=15 to find the distance
Okay thank you!
Sorry I was "out of my mind" Suppose the body travels a distance ds, during a small time interval dt. During this time, we can consider velocity as constant so \[ds=vdt\] distance s is the integral from t=0 to t=15 so we get \[s=\int_{t=0} ^{t=15} (20+7\cos t) dt\] feets
u r welcome..
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