Question

Consider the function f(x) = x^2-25/x+4
IS the VA = -4
is the HA = +/- 5
is the OA = x

Answer 1

x^2-x-12/x-4
Are these correct?
disc = 4
x int = (-3,0)
y int = (0,3)
basic shape= straight line

Answer 2

\[\frac{x^2-x-12}{x-4} = \frac{(x-4)(x+3)}{x-4} = x+3\]
So, your stuff yep looks good.

Answer 3

are both problems correct?

Answer 4

Original post) Remember you will have either a HA or an OA but not both

Answer 5

so there is no HA on that problem

Answer 6

Good. No HA. VA looks good. To get the OA do long division. Looks like y = x + something

Answer 7

| |
x | + | 4 | | x | - | 4
x^2 | + | 0 | - | 25
x^2 | + | 4 x | |
| | -4 x | - | 25
| | -4 x | - | 16
| | | | -9

Answer 8

OA = x+4 or x-4 .. i forget

Answer 9

Right, don't forget the "missing term"
OA looks to be y = x-4

Answer 10

thank you

Answer 11

Cheers!