What is the fourth term of (x + y)8?
56x3y5 36x3y5 36x4y4 56x5y3
for binomial expansions use the formula \[(a + b)^n = ^{n}C _{r} a^{n-r}b^{r}\] and the binomial will have n + 1 terms so for the 4th term r = 3 the expansion is \[^{8}C _{3}x^{8-3}y^3\]
b?
an easy check, for the exponents; is to start at the given exponent; 8 in this case count down the number of terms it wants; 4 terms 8 7 6 5 ; the last number is going to be the exponent of your "front" term
so is the answer 5?
5 is part of the answer; where does this 5 need to be located ?
i dont know,where should it be?
on "the exponent of your 'front' term"
this isnt a solution of course, but a property that you can check to narrow the down the options
ow,thanks,i get it now
good :) the only vagueness might be in what consititues a front term
from there,how do u narrow down to the real answer then?
numbers are read from left to right, --> in this direction the front term that has any merit to me is the "x" since it is first in the original setup. look for an x^5
d?
d is nice yes
is it a and b?
neither a nor b have a x^5 in them, so we can ignore them
ow,i thought u meant, x raised to 5,
i did. so x^3 does not fit the bill
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