Question

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

y = two thirdsx − 10

y = two thirdsx + 10

y = −three halvesx − 10

y = −three halvesx + 10

Answer 1

first change 2x-3y = 3
into this form y = mx + b

where m is the slope and b is the y-intercept
perpendicular lines have a negative reciprocal slope of the other (-1/m)

change the equation into the form y = mx + b to find m then find the equation for the perpendicular line

Answer 2

i cant find it :/

Answer 3

2x-3y=3
minus 2x from both sides
-3y = 3 - 2x
divide by -3 both sides
y = (2/3)x - 1

so the slope of the line is 2/3
the slope of the perpendicular line will be -3/2

y = -(3/2)x + b
substitute x = -8, y = 2 to find b

Answer 4

-3y = -2x+3... divide -3 from y you get.. y=2/3x+1.. take your point.. and put it in point slope formula. y-y1 = 2/3(x+8).. so you get y-2 = 2/3(x +8) add 2 to both sides.. it is y=2/3x+10

Answer 5

@cvickery perpendicular line has negative reciprocal (-1/m) slope, no? o,o

Answer 6

Yeah you are correct on that @nphuongsun93 I derped.

Answer 7

so0 hard :/

Answer 8

lol @pleasehelpme54
do this anyway

y = -(3/2)x + b
substitute x = -8, y = 2 to find b

Answer 9

i did

Answer 10

I believe you are asking someone to do all the work for you... Which I understand but he can't set it up for you any more clearer. 2 = -(3/2)(-8) + b.. 2 = 12 + b b = -10.. so the equation is.. y = (-3/2)x + - 10

Answer 11

- 10* so its D on your thing.. I guess?

Answer 12

y = -(3/2)x + b
substitute x = -8, y = 2 to find b

2 = -(3/2)(-8) + b
2 = 12 + b
b = -10

y = -(3/2)x - 10

it's C lol

Answer 13

C yeah.. okay.. jeeze I am doing bad today with multiple choice.

Answer 14

lol thnks