Question

URGENT: Math word problem

Answer 1

""A popular size of scuba-diving tank is 71.2 ft3 because this is the volume that the compressed air inside the tank would occupy at a normal surface pressure of 1 atm. The air in the tank is at a pressure of about 2250 lb/in.2, so the tank itself can have a volume much less than 71.2 ft3. How large does the tank need to be to hold 71.2 ft3? (Hint: Use Boyle's Law: PV = k. Remember that 1 atm = 14.7 lb/in.2.)"

Answer 2

can someone help me determine the equation I need to have in order to get the answer...? I believe it is 0.465 ft cubed, but I have to show the work and equation..

Answer 3

First convert 71.2 cu. ft into cu. in. or vice versa.
Then P1V1=P2V2

Answer 4

What is the value of P1, V1, P2, and V2?
I'm kinda confused :(

Answer 5

P1 = Pressure1 = 14.7 lb/in.2
V1 = Volume1 = 71.2 ft3
P2 = 2250 lb/in.2
V2 = what you are solving for

Answer 6

are you sure this is correct? Using your method I got 803.81952 as my answer.. and in the answer sheet it says 0.465 :s

Answer 7

I used 123 033.6 inches cubed as the conversion of 71.2 feet cubed.

Answer 8

You actually can skip the unit conversion\[14.7\frac{lb}{in^2}71.2ft^3=x*2250\frac{lb}{in^2}\]\[\frac{14.7*71.2}{2250}\frac{lb*ft^3in^2}{in^2lb}=x\]

Answer 9

amazing!!!! thank you so much :) :)