Question

Find the General Solution:
y'-2y=t^2*e^2t

Answer 1

i got this far
integration factor:
\[\mu(t)=e ^{-2t}\]
\[e ^{-2t}y=\int\limits e ^{2t} (t^2 e ^{2t})dt\]

Answer 2

:)

Answer 3

once you have the integration factor, multiply the entire differential equation by it. You'd getNow simplify algebraically and then integrate.