Question

help ! :D (Sinx/2 + cosx/2) squared =?

Answer 1

(Let us actually square it as follows a^2 + 2ab + b^2

Answer 2

sin^2 + 2sinx/2 cos x/2 + cos^2 x/2

Answer 3

\[\huge (\frac{\sin x}{2} + \frac{\cos x}{2})^2\]
you know that\[(a + b)^2 \implies a^2 + 2ab + b^2\]
so this one is just \[\Large \implies (\frac{\sin x}{2})^2 + 2(\frac{\sin x}{2} \times \frac{\cos x}{2}) + (\frac{\cos x}{2})^2\]
so if you simplify that you get
\[\implies \frac{\sin^2 x}{4} + 2\left (\frac{\sin x \cos x}{4} \right) + \frac{\cos ^2 x}{4}\]
are you getting the idea?

Answer 4

Camjan the sum of \[\sin^2 \frac{ x }{ 2 } + \cos^2 \frac{x}{2} = Very Easy\]

Answer 5

and\[2 \sin \frac{ x }{ 2 } \cos \frac{ x }{ 2 } = \sin 2*\frac{ x }{ 2 } = \sin x\]

Answer 6

Alltogether the CORRECT SOLUTION is\[1 + \sin x\]

Answer 7

\[(Sin x/2 + \cos x/2)^2\]

Answer 8

aand the correct gratitude for correct solution is a M...

Answer 9

\[\sin^2 x/2 + \cos^2 x/2 + 2\sin x/2 * \cos x/2\]

Answer 10

\[\left( \sin \frac{ x }{ 2 } + \cos \frac{ x }{2}\right)^{2} = \]
maybe for you its easy but for me its not that easy thats why i asked you. i just wanna see the step by step solution tnx :)

Answer 11

Camjan read my solution and USE the fact that\[\sin^2 \frac{ x }{ 2 } + \cos^2 \frac{ x }{ 2 } = 1\]

Answer 12

1 + 2sin x/2 * cosx/2

= 1 + sin 2 * x/2 = 1 + sinx

Answer 13

This is what I meant by "very Easy" Right hand side

Answer 14

i cant understand what our teacher taught us she's so fast .. pls help me guys my exam is tomorrow

Answer 15

@camjan Did u understand..

Answer 16

oh ok :) tnx

Answer 17

Mr Yahoo seems to re-type EVERY LINE I WROTE TO YOU ( but in bad writing :(

Answer 18

And by the way - a medal is due, and closing the question

Answer 19

@Mikael hahaha.. its ok

Answer 20

oh...Sorry....@Mikael i didnt see..that

Answer 21

Any way u deserve a Medal