Rationalize the denominator of sqrt(5/13) and sqrt(x/6) and sqrt(y/2z)
these are the problems I need to rationalize the denominator for \[\sqrt(5/13)\] also \[\sqrt(x/6)\] also \[\sqrt(y/2z)\]
Just Multiply each one of them by the \[\sqrt{Denomin}\] both the Top and the bottom should be multiplied
Example the first shld be multiplied by \[\sqrt{13}\] BOTH ABOVE AND BELOW THE FRACTION LINE
then ur denom becomes rational = 13
Use of course this \[\sqrt{A}*\sqrt{B} = \sqrt{AB}\]
\[\sqrt\frac 5{13}=\sqrt{\frac 5{13}}\times 1\]\[\qquad\qquad=\sqrt\frac 5{13}\times\sqrt\frac{13}{13}\]\[\qquad\qquad=\sqrt\frac 5{13}\times\sqrt\frac{13}{13}\]\[\qquad\qquad=\frac{\sqrt{5}\sqrt{13}}{13}\]
This is NOT COMPLETE to the end - it should be written
\[\frac{ \sqrt{65} }{ 13 }\]
SPOTLESS HAVE U GOT MY IDEA ?
O.K. good and farewell :)
Yes Mikael, once again it's very much appreciated. I found a youtube tutorial to better explain the concept you've just showed me. Appreciate the help!
Glad to make ur life easier a bit :)
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