Question

Sue plans to paste two ribbons along the diagonals of the top surface of a rectangular gift box, as shown below.



What is the minimum length of ribbon that Sue would require?

28 inches

10 inches

100 inches

20 inches

Answer 1

@tyteen4a03 @ParthKohli

Answer 2

@Hero

Answer 3

Use the Pythagorean Theorm to solve this. In this case, substitute 8 and 6 into the equation, we have \[8^2 + 6^2 = c^2\]
Solve this equation and multiply it by 2 (\(8^2 + 6^2 = 6^2 + 8^2\))

Answer 4

64+36+36+64=200

Answer 5

@jim_thompson5910

Answer 6

@cfraser007

Answer 7

@ganeshie8

Answer 8

since top is of rectangle shape, the diagonals are congruent

Answer 9

length of ribbon required = 2 * diagonal

= \(2\sqrt{8^2+6^2}\)

= ?

Answer 10

so 50?

Answer 11

how.. thats not even there in the options. how did u get that... hmm

Answer 12

= \(2\sqrt{64 + 36}\)

= \(2\sqrt{100}\)

= ?

Answer 13

2 divided by 100?

Answer 14

idk i was trying to figure it out

Answer 15

hey that symbol is square-root

Answer 16

okay so how do i do that

Answer 17

you familiar with squares & square-roots ?

Answer 18

for ex :

\(5^2 = 25\)

\(\sqrt{25} = 5\)