Question

Identify whether the statement is sometimes, always, or never true:

Answer 1

\[\sqrt{2x+5}-4 \le x-2\]

Answer 2

Do some algebra on it... try and get rid of the square root.

Answer 3

sooo i know i have to square each side in order to do that. i'd end up with

2x+5-16 le x^2 - 4, right/?

Answer 4

is less than/equl to* x^2 - 4

Answer 5

no. You want to isolate the square root first. If you square (sqrt(2) + 1) then you'll end up with square root terms again.

Answer 6

^ for example.

Answer 7

nopes,
(a-b)^2 is not just a^2-b^2
(a-b)^2=a^2-2ab+b^2
but here before squaring,u need to add 4 on both sides...

Answer 8

ugh i hate algebra. one minute

Answer 9

This is more like arithmetic. Arithmetic is boring. Algebra is pretty good.

Answer 10

I'll come back to this one. i have other questions