Identify whether the statement is sometimes, always, or never true:

Question

rainbow_dash · Answer

$$\sqrt{2x+5}-4 \le x-2$$

anonymous · Answer

Do some algebra on it... try and get rid of the square root.

rainbow_dash · Answer

sooo i know i have to square each side in order to do that. i'd end up with

2x+5-16 le x^2 - 4, right/?

rainbow_dash · Answer

is less than/equl to* x^2 - 4

anonymous · Answer

no. You want to isolate the square root first. If you square (sqrt(2) + 1) then you'll end up with square root terms again.

anonymous · Answer

^ for example.

hartnn · Answer

nopes,
(a-b)^2 is not just a^2-b^2
(a-b)^2=a^2-2ab+b^2
but here before squaring,u need to add 4 on both sides...

rainbow_dash · Answer

ugh i hate algebra. one minute

anonymous · Answer

This is more like arithmetic. Arithmetic is boring. Algebra is pretty good.

rainbow_dash · Answer

I'll come back to this one. i have other questions