Find a polynomial function that has the given zeros.
1 + sqrt3, 1 - sqrt 3
a polynomial has a zero at \(x=a\) iff \(x-a\) is a factor of the polynomial
so to make a polynomial that has two zeroes, x=a and x=b, the factors should be\[(x-a)(x-b)\]
Yeah, I understand how to do them, I'm just really confused on when I'm looking a function with a zero with a square root involved
in your case \[a=1+\sqrt2\]and\[b=1-\sqrt3\]so what are your factors?
Is my answer just going to be f(x)= (-1 - sqrt3)(-1 + sqrt3) ?
what happened to x ? o_O
...and no, you probably should multiply it out anyway... once it's set up right that is
Yeah, I'll multiply it. I just don't know how to set it up right. 3:
(x-a)(x-b)=? sub in for a and b
f(x) = (x + 1 - sqrt3) (x + 1 + sqrt3)?
and multiplied out, which I will do if I know this is right.
not quite...
(x-a)(x-b)=[x-(1+sqrt3)][x-(1-sqrt3)]=?
So I just needed to add the extra parentheses..?
you messed up with the +/- stuff, gotta be more careful I set it up for you so all you have to do is simplify
Thank you so much!!!!!! :)
welcome!
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