Ask your own question, for FREE!
Mathematics 27 Online
OpenStudy (anonymous):

Find a polynomial function that has the given zeros.

OpenStudy (anonymous):

1 + sqrt3, 1 - sqrt 3

OpenStudy (turingtest):

a polynomial has a zero at \(x=a\) iff \(x-a\) is a factor of the polynomial

OpenStudy (turingtest):

so to make a polynomial that has two zeroes, x=a and x=b, the factors should be\[(x-a)(x-b)\]

OpenStudy (anonymous):

Yeah, I understand how to do them, I'm just really confused on when I'm looking a function with a zero with a square root involved

OpenStudy (turingtest):

in your case \[a=1+\sqrt2\]and\[b=1-\sqrt3\]so what are your factors?

OpenStudy (anonymous):

Is my answer just going to be f(x)= (-1 - sqrt3)(-1 + sqrt3) ?

OpenStudy (turingtest):

what happened to x ? o_O

OpenStudy (turingtest):

...and no, you probably should multiply it out anyway... once it's set up right that is

OpenStudy (anonymous):

Yeah, I'll multiply it. I just don't know how to set it up right. 3:

OpenStudy (turingtest):

(x-a)(x-b)=? sub in for a and b

OpenStudy (anonymous):

f(x) = (x + 1 - sqrt3) (x + 1 + sqrt3)?

OpenStudy (anonymous):

and multiplied out, which I will do if I know this is right.

OpenStudy (turingtest):

not quite...

OpenStudy (turingtest):

(x-a)(x-b)=[x-(1+sqrt3)][x-(1-sqrt3)]=?

OpenStudy (anonymous):

So I just needed to add the extra parentheses..?

OpenStudy (turingtest):

you messed up with the +/- stuff, gotta be more careful I set it up for you so all you have to do is simplify

OpenStudy (anonymous):

Thank you so much!!!!!! :)

OpenStudy (turingtest):

welcome!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!