Question

Find 3 consecutive odd integers such that when the 1st is subtracted from 4 times the 3rd, the result is 7.

Answer 1

Well, if x is the first of the three integers, what are the other two (in terms of x)

Answer 2

x+2 and X+3, i never now how to put this into an equation to solve, thats my only problem

Answer 3

Well, the second one is x+2, but the third one is x+4 (because odd numbers skip by 2)

Answer 4

*4 sorry yeah

Answer 5

OK, so the first subtracted from 4 times the 3rd would look like what?

Answer 6

x-4(x+4)

Answer 7

Almost, but it's 4(x+4)-x (since you're subtracting the first away from the 4th)

Answer 8

Okay so the answer would be x=23/3

Answer 9

I'm just going to go out on a limb here and point out that 23/3 isn't an integer

Answer 10

ohhhhh....

Answer 11

yeah....lol

Answer 12

I wrote the whole problem like this : 4(x+4)-x=7

Answer 13

Distributed the 4... that gets me to, 4x+16-x+7?

Answer 14

It's sort of a trick... the answer is going to be negative

Answer 15

*=7

Answer 16

Did you mean 4x+16-x=7 ?

Answer 17

yes

Answer 18

OK, keep going

Answer 19

4x-x=3x

so 3x+16=7

Answer 20

Yup

Answer 21

subtract the 16 next?

Answer 22

Good plan

Answer 23

oohh -9, that gets me -3.

Answer 24

Right! You should check your answer, but the three integers are -3, what, and what?

Answer 25

-1, -3, -5?

Answer 26

Ummm, -3 is the first of the 3, so not quite

Answer 27

or -3,-5,and-7

Answer 28

Well, remember, the second is x+2 not x-2

Answer 29

ok

Answer 30

where those right?

Answer 31

Nope, because -5 is -3-2, not -3+2

Answer 32

the answer is :5,7,9

Answer 33

@oholmes Do you have another guess/answer?

Answer 34

k:integer
so we have 3 odd integers:2k+1,2k+3,2k+5
2k+5-4(2k+1)=7
so k=2
that's why the 3 odd integers are:5,7,9

Answer 35

@echo_ed so 4*9 - 5 = 7 ???

Answer 36

ohhhhh

Answer 37

sorry

Answer 38

OK, @oholmes did most of the work here, so the answer is: -3, -1 and +1