HELPP Suppose that a sphere with radius 5a has the same volume as a cone of radius 3a. What is the height of the cone? Give your answer in terms of a. Use the formulas and for the volumes of a sphere and cone respectively.
FORMULAS : \[V=\frac{ 4 }{ 3 } \pi r ^{3}\] \[V = \frac{ 1 }{ 3 }\pi r ^{2} h\]
just put r=5a in 1st equation r=3a in 2nd equation. then divide 1st equation by 2nd equation. u will get h after simplification.
i got \[\frac{ 20 }{ 3 }\]
nopes.....also there should be 'a' in your answer
answers .. b. \[\frac{ 500 }{ 9 }a\] c. \[\frac{ 9 }{ 500 }a ^{2}\] d. \[\frac{ 500 }{ 9 }a\]
these are the possible answers
\[4(125a^3)=(9a^2)h\] so \[h=\frac{125*4*a^3}{9a^2}\]
can u solve further?
whats the difference between option b and d ??
b is suppose to be a squared sorry !
so can u get h from \[h=\frac{125*4*a^3}{9a^2}\] ?
wouldnt it be d ? i think ...
125*4=500
yup :)
so its d i got it right
yes,its d
thank you so much for the help !
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