HELPP
Suppose that a sphere with radius 5a has the same volume as a cone of radius 3a. What is the height of the cone? Give your answer in terms of a. Use the formulas and for the volumes of a sphere and cone respectively.
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OpenStudy (erinweeks):
FORMULAS : \[V=\frac{ 4 }{ 3 } \pi r ^{3}\]
\[V = \frac{ 1 }{ 3 }\pi r ^{2} h\]
hartnn (hartnn):
just put r=5a in 1st equation
r=3a in 2nd equation.
then divide 1st equation by 2nd equation.
u will get h after simplification.
OpenStudy (erinweeks):
i got \[\frac{ 20 }{ 3 }\]
hartnn (hartnn):
nopes.....also there should be 'a' in your answer
OpenStudy (erinweeks):
answers ..
b. \[\frac{ 500 }{ 9 }a\]
c. \[\frac{ 9 }{ 500 }a ^{2}\]
d. \[\frac{ 500 }{ 9 }a\]
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OpenStudy (erinweeks):
these are the possible answers
hartnn (hartnn):
\[4(125a^3)=(9a^2)h\]
so
\[h=\frac{125*4*a^3}{9a^2}\]
hartnn (hartnn):
can u solve further?
hartnn (hartnn):
whats the difference between option b and d ??
OpenStudy (erinweeks):
b is suppose to be a squared sorry !
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hartnn (hartnn):
so can u get h from
\[h=\frac{125*4*a^3}{9a^2}\]
?
OpenStudy (erinweeks):
wouldnt it be d ? i think ...
hartnn (hartnn):
125*4=500
hartnn (hartnn):
yup :)
OpenStudy (erinweeks):
so its d i got it right
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