what is the period of 1/(2+sinx)? and how do you get it?
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OpenStudy (anonymous):
ok, just a second
OpenStudy (anonymous):
i think its 2pi
OpenStudy (anonymous):
just shifted to the left by pi compared to the sinx function
OpenStudy (anonymous):
yes, there is that as well, but period doesnt matter about vertical shifts correct?
OpenStudy (anonymous):
oh, i meant 1/(2+sinx)
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OpenStudy (anonymous):
oh... that changes things....
OpenStudy (anonymous):
sorry :(
OpenStudy (anonymous):
one second....
OpenStudy (anonymous):
do you know calculus?
OpenStudy (anonymous):
yes, this is for my partial differential equations class
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OpenStudy (anonymous):
all the way past calc 3
OpenStudy (anonymous):
because the only way i can think of finding the period is to find the maximum of the function and figure out the distance from each maximum...
OpenStudy (anonymous):
***between maximums..
OpenStudy (anonymous):
can i do that on a calculator??? or...
OpenStudy (anonymous):
ok.... \(\large f(x) = \frac{1}{2+sinx} \)
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OpenStudy (anonymous):
yup
OpenStudy (anonymous):
on a calculator, sure you can.....
OpenStudy (anonymous):
you wanna just do it with calculator instead of finding the maximums?
OpenStudy (anonymous):
with calculus?
OpenStudy (anonymous):
nope, calc is better
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OpenStudy (anonymous):
ok... hang on a sec...
OpenStudy (anonymous):
this is the online calculator i'm using:
https://www.desmos.com/calculator
it finds the "points of interests" meaning the max/mins.. here's a screen shot...
OpenStudy (anonymous):
ok, that is much clearer than my calculator
OpenStudy (anonymous):
putting my cursor on the two adjacent maximums gives x=-pi/2 and x=3pi/2 as the x coordinates of the maximums.
OpenStudy (anonymous):
so 2pi
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OpenStudy (anonymous):
haha... yep....
OpenStudy (anonymous):
i was afraid you wanted to take derivatives! :)
OpenStudy (anonymous):
OpenStudy (anonymous):
lol, i attached the wrong one!!!!!!
OpenStudy (anonymous):
oh wow .... thanks for the bank account number... :)
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OpenStudy (anonymous):
kidding!
OpenStudy (anonymous):
yeah, no problem!!!! i know you are just itching to do my mathlab hw!
OpenStudy (anonymous):
awww , i thought i could enjoy more math problems to take me through the night!
OpenStudy (anonymous):
lol, i got another....
OpenStudy (anonymous):
ok... couldu make a new post ? thnks....:)
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