Question

Given the intersects of a parabola, how do you find p and q in the equation y = a(x-p)(x-q)?

Answer 1

The X intersects* Meant to specify.

Answer 2

p and q are the x intersects
a is the value of the y intersect when x = 0

Answer 3

actually: "apq" would be the value of the y intercept when x=0

Answer 4

the answer is already given!
Because the intercepts(intersects) of the parabola(which is a vertical parabola) y=a(x-p)(x-q) are simply the valuse which go in place of p and q and make the value of y zero! so these values could be found by setting the value of y=0=a(x-p)(x-q)
and clearly for this value to be zero either a=0 or x-p=0 or x-q=0
so the solutions are a=0 or x=p or x=q but a=0 implies the value of the y intercept(x=0)
and the x interceps(or the points wher the parabola crosses the x axis are)
x=p and x=p
so the points on the co-ordinate system are
(p,0) and (q,0)

Answer 5

silly me - thanx amistre :- apq