1/x-1 + 1/x+2 = 5/4 solve for all solutions?
Multiply both sides by 4(x-1)(x+2) and see what you can get
\[ 4 (x-1) (x+2) \left(\frac{1}{x+2}+\frac{1}{ x-1}\right)=\frac{5}{4} 4 (x-1) (x+2) \]
\[ \frac{4 (x-1) (x+2)}{x-1}+\frac{4 (x-1) (x+2)}{x+2}=\frac{5}{4} 4 (x-1) (x+2) \] Simplify now.
\[ 4 (x-1)+4 (x+2)=5 (x-1) (x+2) \]
\[ 8 x+4=5 x^2+5 x-10 \]
Can you finish it now?
yeah thx i understand now
Actually x = 2 is one of the solutions since 2 + 2 = 4
I thought x-2 was one of the denominator. I should have looked up.
Yeah, I do the fractions on paper first before posting now to avoid mistakes like that. Actually, I have a technique that I use to make sure any extraneous roots are canceled before solving so I never run into that problem.
And in this case, there were no extraneous roots.
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