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Mathematics 15 Online
OpenStudy (anonymous):

Put the function P=156(0.9)^t in the form P=Poe^kt. Po= k= Help Please!

OpenStudy (anonymous):

start by setting 156(0.9)^t equal to Poe^(kt)

OpenStudy (anonymous):

how do i solve for them though? i dont know the variables value!

OpenStudy (anonymous):

Well we can start off right away sayting the P0 = 156

OpenStudy (anonymous):

then what? sorry im a bit clueless!

OpenStudy (anonymous):

ohhhh, we end up with \[(0.9)^{t}=e^{kt}\]

OpenStudy (anonymous):

now we want to take the ln of both sides

OpenStudy (anonymous):

t*ln(0.9)=kt?

OpenStudy (anonymous):

yes, solve for k, go for it!

OpenStudy (anonymous):

-0.1053605157!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

Thanks so much!

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