What is the solution of the system? Use substitution. x = –2y + 10 –6y = 6x – 6 z = –3x + 10y A. x = 9, y = –8, z = 114 B. x = –8, y = 9, z = 114 C. x = –8, y = 114, z = 9 D. x = 114, y = 9, z = –8
i know it is not (C)
If it's multiple choice, it would be just as much or less work to just try all the possible solutions.
Otherwise, a good first step is to reduce the second equation by dividing it by -6.
i am thinking it is (A)
From there, since the first two equations have the same two unknowns, you can solve that system first for x and y, and then sub. into eq.3 for z.
after dividing by -6 add 1st 2 equations,u will get x and y
so it is not (A)
no, not A
=(
I like substitution for this one. Just using the top two eqn's you can get x and y wich leads to the answer.
first divide the 2 eqn by 6 and note the value of -y. Then multiply the the value of -y with 2.Substitute this value to eqn 1 and you will get the value of x i.e -8. now solve for y by using any eqn. the value of y=9. nNow substituting the value of both x and y in third eqn we get 114. So the answer to the ques is B
thank you
Join our real-time social learning platform and learn together with your friends!