Mathematics
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OpenStudy (anonymous):
3x^2+2x+6x+4
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OpenStudy (anonymous):
what do you get when you add like terms
OpenStudy (turingtest):
how many terms have x^2 in them?
OpenStudy (anonymous):
3x^2+8x^2+4
OpenStudy (turingtest):
not quite
just add the coefficients of the like terms, do not change the x part...
OpenStudy (anonymous):
by the way im doing trinomial factoring
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OpenStudy (anonymous):
3x^2+8x+4
OpenStudy (anonymous):
start like this
\[(x _{1}+y _{1})(x _{2}+y _{2})\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
you know that the fist x multiplied by the second is \[3x ^{2}\]
so it would be safe to say, one is 3X and the other is just X
OpenStudy (anonymous):
ok so is this the final answer(3x-2)(x+8)
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OpenStudy (anonymous):
If you're factoring, don't add like terms from the original expression, just factor in groups.
OpenStudy (anonymous):
no, because \[-2\times8\neq4\]
OpenStudy (anonymous):
ok so is it (3x-2) (x+4)
OpenStudy (anonymous):
the last term in the trinomial is \[y _{1}\times y _{2}\]
OpenStudy (anonymous):
ok so what would the answer be then
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OpenStudy (anonymous):
(3x+1)(x+4)
OpenStudy (anonymous):
i checked my answer and i found that to be incorrect
OpenStudy (anonymous):
(3x²+6x) + (2x + 4)
=3x ( x + 2 ) + 2 ( x + 2 )
Can you factor them now?
OpenStudy (anonymous):
|dw:1346447748307:dw|ok then, the first factor in a trinomial is foud by these
OpenStudy (anonymous):
(x+2)(3x+2)
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OpenStudy (anonymous):
Yupeee :)
OpenStudy (anonymous):
thanks!!!