Geometry question (figure in comments)
1. calculate DE
2. calculate EG
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OpenStudy (anonymous):
OpenStudy (anonymous):
@ganeshie8 any help?
ganeshie8 (ganeshie8):
similar triangles
ganeshie8 (ganeshie8):
DE is the geometric mean between the hypotenuse and the segment of the hypotenuse next to DE.
ganeshie8 (ganeshie8):
one thing at a time. lets calculate DE first :)
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ganeshie8 (ganeshie8):
hypotenuse = DF = 3+8 = 11
right ?
OpenStudy (anonymous):
yes
ganeshie8 (ganeshie8):
now DE is the geometric mean between hypotenuse & segment next to DE
=>
DE = \(\sqrt{3*11}\)
OpenStudy (anonymous):
5.7?
ganeshie8 (ganeshie8):
thats right ! you can leave it as \(\sqrt{33}\) also, unless the question explicitly asks for decimal form
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OpenStudy (anonymous):
ok cool so DE would be what I said earlier?
OpenStudy (anonymous):
root 55?
ganeshie8 (ganeshie8):
you mean EG ?
OpenStudy (anonymous):
EG sorry, yes
ganeshie8 (ganeshie8):
thats not correct. looks something went wrong in ur calculation s...
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OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
if you see , EG is the altitude from vertex E to hypotenuse
OpenStudy (anonymous):
right
ganeshie8 (ganeshie8):
The length of the altitude is the geometric mean between the segments of the hypotenuse
ganeshie8 (ganeshie8):
=>
EG = \(\sqrt{3*8}\)
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ganeshie8 (ganeshie8):
does that make sense ?
OpenStudy (anonymous):
2 root 6
ganeshie8 (ganeshie8):
thats right !!
OpenStudy (anonymous):
thank you!
ganeshie8 (ganeshie8):
for solving these you just need to remember two things :
1) The length of the altitude in these right triangles is the geometric mean between the segments of the hypotenuse.
2) Each leg is also a geometric mean between the hypotenuse and the segment of the hypotenuse next to the given leg.
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ganeshie8 (ganeshie8):
yw.. .:D
OpenStudy (anonymous):
I have one more problem if you dont mind?
ganeshie8 (ganeshie8):
sure post :)
OpenStudy (anonymous):
ganeshie8 (ganeshie8):
soh-cah-toa
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OpenStudy (anonymous):
Calculate for cos, sin, and tan.
OpenStudy (anonymous):
Yes sohcahtoa
ganeshie8 (ganeshie8):
you giving segment-one exam right :)
OpenStudy (anonymous):
exam?
ganeshie8 (ganeshie8):
nvm :)
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OpenStudy (anonymous):
oh okay lol
ganeshie8 (ganeshie8):
look the triangle from \(\theta\)
OpenStudy (anonymous):
okay
ganeshie8 (ganeshie8):
you goto \(\theta \) corner, sit there and look
ganeshie8 (ganeshie8):
can you identify below two :
1) adjacent side
2) opposite side
?
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OpenStudy (anonymous):
adjacent is 10, opposite is 10?
OpenStudy (anonymous):
*12
ganeshie8 (ganeshie8):
hypotenuse = 12,
there wont be any change in hypotenuse, no matter from which corner you see the triangle ok
OpenStudy (anonymous):
okay
ganeshie8 (ganeshie8):
adjacent side = 10, as it is the one next to \(\theta\)
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