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Mathematics 16 Online
OpenStudy (anonymous):

Can anyone help me, please ?

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

\[\Large \sqrt{48}\] \[\Large \sqrt{16*3}\] \[\Large \sqrt{16}*\sqrt{3}\] \[\Large 4*\sqrt{3}\] So \[\Large \sqrt{48} = 4*\sqrt{3}\]

jimthompson5910 (jim_thompson5910):

Use this idea to simplify the other roots. Then combine like terms.

jimthompson5910 (jim_thompson5910):

Tell me what you get when you simplify them.

OpenStudy (anonymous):

Okay... one second.

jimthompson5910 (jim_thompson5910):

alright

OpenStudy (anonymous):

So it is either b or c.

jimthompson5910 (jim_thompson5910):

what makes you say that?

OpenStudy (anonymous):

OH, wait ..it's A. I think.

jimthompson5910 (jim_thompson5910):

\[\Large \sqrt{75}\] \[\Large \sqrt{25*3}\] \[\Large \sqrt{25}*\sqrt{3}\] \[\Large 5*\sqrt{3}\] This means \[\Large \sqrt{75} = 5*\sqrt{3}\]

jimthompson5910 (jim_thompson5910):

\[\Large \sqrt{192}\] \[\Large \sqrt{64*3}\] \[\Large \sqrt{64}*\sqrt{3}\] \[\Large 8*\sqrt{3}\] This means \[\Large \sqrt{192} = 8*\sqrt{3}\]

OpenStudy (anonymous):

I'm still confused.

jimthompson5910 (jim_thompson5910):

Put it all together to get... \[\Large \sqrt{48}-\sqrt{75}+\sqrt{192}\] \[\Large 4*\sqrt{3}-5*\sqrt{3}+8*\sqrt{3}\] \[\Large (4-5+8)*\sqrt{3}\] \[\Large 7\sqrt{3}\] So \[\Large \sqrt{48}-\sqrt{75}+\sqrt{192}=7\sqrt{3}\]

OpenStudy (anonymous):

That's where I got confused, in the parenthesis.

jimthompson5910 (jim_thompson5910):

you basically factor out the GCF sqrt(3) and you combine like terms

OpenStudy (anonymous):

See that's what I was missing,.

jimthompson5910 (jim_thompson5910):

does it all make sense now?

OpenStudy (anonymous):

Um, yes I understand it beteter.

OpenStudy (anonymous):

*better.

jimthompson5910 (jim_thompson5910):

alright that's great

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