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|(z)-(z/3)|=1 find the range to which |z| belongs
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z is complex? If so z=x+iy \[|x+iy-\frac{x+iy}{3}|=1\]
\[|\frac{2x+2iy}{3}|=1\] \[\frac{2x+2iy}{3}\] Is just some other complex number with real part\[\frac{2}{3}\] and imaginary part also\[\frac{2}{3}\]
|dw:1346582805455:dw| Where w is that complex number. Find the modulus by pythagoras, and you have an equation with a, b and constants.
\[|w|=\sqrt{(\frac{2x}{3})^2+(\frac{2y}{3})^2}=1\]
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